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Bogut Breaks Ankle, Bucks Play Bulls tonight

by
Milwaukee Bucks logo.
Milwaukee Bucks logo.

CHICAGO, Ill (WSAU) Milwaukee Bucks' center Andrew Bogut will be out indefinitely after he broke his left ankle in Wednesday night's win at Houston. It's yet another setback for the seven-foot Australian -- but he tweeted that it was beyond his control and quote, "I will get back from this."

Bogut was trying to block a shot when his foot came down awkwardly on a Houston player's foot. An M-R-I yesterday uncovered the break in the ankle. Bogut was playing in his 400th career N-B-A game when he was hurt. He has averaged around 11 points, eight-and-a-half rebounds, and two blocked shots in a dozen games this season.

Bogut was hoping to be healthy this season, after wrist-and-arm injuries hampered him for most of last year. But Bogut missed the January 13th game against Dallas with concussion-like symptoms -- and he then missed four games when he went back home to Australia for a personal matter.

The Bucks have won three straight road games, and will play at Chicago tonight.

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